Click here👆to get an answer to your question ️ derive the condition for balance of a wheatstones bridge using When the current is flown through the circuit and galvanometer does not give any deflection, then the bridge is balanced and when the bridge is balanced, then P Q = R S This is the principle of Wheatstone bridge . Let the current i is divided into two parts i1 and i2 flowing through P, Q and R, S respectively. Wheatstone bridge (balanced) - Let i be the current from battery E .At point A , current i1 flows through resistance P and current i−i1 flows through R. In balanced state , no current flows through BD , hence point B and D are at same potential .Therefore current i1 flows through resistance Q also and current i−i1 flows through S. Using the principle of Wheatstone Bridge ,describe the method to determine the specific resistance of a wire in the laboratory.Draw the circuit diagram and write the formula used. Write any two important precautions you would observe while performing the experiment. OR Draw a circuit diagram of Metre Bridge and write the mathematical relation used to determine the value of an unknown resistance.Why cannot such as arrangement be used for measuring very low resistance? OR a) State,with the ...
